What is the average speed of Julie if it took her ¾ of an hour to run 3½ miles?

What is the average speed of Julie if it took her ¾ of an hour to run 3½ miles?

• A. 3 ⅔ miles per hour
• B. 4 ⅓ miles per hour
• C. 4 ⅔ miles per hour
• D. 4 ½ miles per hour

Answer: (C)

To find the average speed, you need to use the formula for speed, which is distance divided by time. In this case, Julie ran a total distance of 3½ miles. To perform the calculations, it’s helpful to convert mixed numbers into improper fractions or decimals. First, let's convert 3½ miles into an improper fraction: 3½ can be expressed as (3 × 2 + 1)/2, which equals 7/2 miles. Next, we know that it took her ¾ of an hour. This can also be expressed as a fraction: ¾ hours is already in fractional form. Now, we can calculate her average speed: Average speed = Distance / Time = (7/2 miles) / (3/4 hours). When dividing fractions, you multiply by the reciprocal of the denominator: = (7/2 miles) × (4/3 hours) = (7 × 4) / (2 × 3) miles per hour = 28/6 miles per hour. Now, we simplify 28/6: 28 divided by 6 equals 4⅔. Therefore, Julie's average speed is indeed 4⅔ miles per hour. This matches the value for the

To find the average speed, you need to use the formula for speed, which is distance divided by time. In this case, Julie ran a total distance of 3½ miles. To perform the calculations, it’s helpful to convert mixed numbers into improper fractions or decimals.

First, let's convert 3½ miles into an improper fraction:

3½ can be expressed as (3 × 2 + 1)/2, which equals 7/2 miles.

Next, we know that it took her ¾ of an hour. This can also be expressed as a fraction:

¾ hours is already in fractional form.

Now, we can calculate her average speed:

Average speed = Distance / Time = (7/2 miles) / (3/4 hours).

When dividing fractions, you multiply by the reciprocal of the denominator:

= (7/2 miles) × (4/3 hours) = (7 × 4) / (2 × 3) miles per hour

= 28/6 miles per hour.

Now, we simplify 28/6:

28 divided by 6 equals 4⅔.

Therefore, Julie's average speed is indeed 4⅔ miles per hour. This matches the value for the